When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 2c = 3c + 3x - 8 for c in terms of x.
| 1\(\frac{2}{3}\)x - 2\(\frac{2}{3}\) | |
| -\(\frac{1}{2}\)x + \(\frac{5}{12}\) | |
| x + \(\frac{1}{7}\) | |
| -\(\frac{3}{4}\)x + \(\frac{1}{4}\) |