When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 9c = -c + z - 5 for c in terms of z.
| 1\(\frac{1}{4}\)z + \(\frac{1}{4}\) | |
| -1\(\frac{3}{5}\)z - 1 | |
| 1\(\frac{4}{7}\)z - \(\frac{3}{7}\) | |
| -\(\frac{1}{3}\)z - 2\(\frac{2}{3}\) |