ASVAB Math Knowledge Practice Test 365522

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4c - 9c = -8c - 6x + 2 for c in terms of x.

\(\frac{3}{4}\)x + \(\frac{1}{2}\)
-x - \(\frac{3}{5}\)
-1\(\frac{1}{5}\)x - \(\frac{1}{5}\)
-1\(\frac{1}{3}\)x + 1\(\frac{1}{3}\)