To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-4b - 1 = \( \frac{b}{-2} \)
-2 x (-4b - 1) = b
(-2 x -4b) + (-2 x -1) = b
8b + 2 = b
8b + 2 - b = 0
8b - b = -2
7b = -2
b = \( \frac{-2}{7} \)
b = -\(\frac{2}{7}\)

You need to find the value of a so solve the first equation in terms of x:

2a + x = -6
x = -6 - 2a

then substitute the result (-6 - 2a) into the second equation:

2a - 7(-6 - 2a) = 9
2a + (-7 x -6) + (-7 x -2a) = 9
2a + 42 + 14a = 9
2a + 14a = 9 - 42
16a = -33
a = \( \frac{-33}{16} \)
a = -2\(\frac{1}{16}\)

The volume of a cube is height x length x width:

v = h x l x w
v = 6 x 4 x 5
v = 120

The formula for area is πr². Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{8}{2} \)
r = 4
a = πr²
a = π(4²)
a = 16π

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

4z + 3 < \( \frac{z}{7} \)
7 x (4z + 3) < z
(7 x 4z) + (7 x 3) < z
28z + 21 < z
28z + 21 - z < 0
28z - z < -21
27z < -21
z < \( \frac{-21}{27} \)
z < -\(\frac{7}{9}\)