ASVAB Math Knowledge Practice Test 366804 Results

Your Results Global Average
Questions 5 5
Correct 0 3.30
Score 0% 66%

Review

1

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
7\( \sqrt{2} \)
3\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)


2

Simplify (9a)(9ab) - (9a2)(2b).

62% Answer Correctly
99ab2
99a2b
63a2b
198a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(9a)(9ab) - (9a2)(2b)
(9 x 9)(a x a x b) - (9 x 2)(a2 x b)
(81)(a1+1 x b) - (18)(a2b)
81a2b - 18a2b
63a2b


3

If a = 3, b = 5, c = 5, and d = 8, what is the perimeter of this quadrilateral?

88% Answer Correctly
23
28
21
15

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 3 + 5 + 5 + 8
p = 21


4

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

acute, obtuse

supplementary, vertical

vertical, supplementary

obtuse, acute


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


5

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

π r2h

2(π r2) + 2π rh

π r2h2

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.