When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 4c = -3c - 9z + 5 for c in terms of z.
| 1\(\frac{1}{2}\)z - 1 | |
| -4\(\frac{1}{3}\)z + \(\frac{1}{3}\) | |
| -\(\frac{5}{7}\)z + \(\frac{5}{7}\) | |
| -\(\frac{12}{13}\)z - \(\frac{2}{13}\) |