ASVAB Math Knowledge Practice Test 36797 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

The endpoints of this line segment are at (-2, 0) and (2, 4). What is the slope of this line?

46% Answer Correctly
\(\frac{1}{2}\)
2\(\frac{1}{2}\)
1
-2\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, 4) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (0.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)
m = 1


2

The dimensions of this cube are height (h) = 2, length (l) = 4, and width (w) = 5. What is the surface area?

51% Answer Correctly
16
76
256
292

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 5) + (2 x 5 x 2) + (2 x 4 x 2)
sa = (40) + (20) + (16)
sa = 76


3

If AD = 19 and BD = 9, AB = ?

76% Answer Correctly
13
15
10
14

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 19 - 9
AB = 10


4

What is 3a6 - 6a6?

73% Answer Correctly
9
a612
-3a6
9a12

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a6 - 6a6 = -3a6


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
2\( \sqrt{2} \)
4\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)