| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.71 |
| Score | 0% | 54% |
Which of the following statements about math operations is incorrect?
you can multiply monomials that have different variables and different exponents |
|
you can subtract monomials that have the same variable and the same exponent |
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all of these statements are correct |
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you can add monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Find the value of c:
-3c + y = -3
-7c + 5y = 9
| 3 | |
| \(\frac{44}{47}\) | |
| -17 | |
| -1\(\frac{3}{5}\) |
You need to find the value of c so solve the first equation in terms of y:
-3c + y = -3
y = -3 + 3c
then substitute the result (-3 - -3c) into the second equation:
-7c + 5(-3 + 3c) = 9
-7c + (5 x -3) + (5 x 3c) = 9
-7c - 15 + 15c = 9
-7c + 15c = 9 + 15
8c = 24
c = \( \frac{24}{8} \)
c = 3
If a = -1 and y = 7, what is the value of -9a(a - y)?
| -306 | |
| -72 | |
| -18 | |
| 40 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-9a(a - y)
-9(-1)(-1 - 7)
-9(-1)(-8)
(9)(-8)
-72
Solve for x:
-2x - 2 > \( \frac{x}{-5} \)
| x > \(\frac{42}{55}\) | |
| x > -1\(\frac{1}{9}\) | |
| x > \(\frac{24}{25}\) | |
| x > -\(\frac{8}{29}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-2x - 2 > \( \frac{x}{-5} \)
-5 x (-2x - 2) > x
(-5 x -2x) + (-5 x -2) > x
10x + 10 > x
10x + 10 - x > 0
10x - x > -10
9x > -10
x > \( \frac{-10}{9} \)
x > -1\(\frac{1}{9}\)
Solve for a:
-4a - 1 = \( \frac{a}{7} \)
| -\(\frac{49}{50}\) | |
| 1\(\frac{1}{39}\) | |
| 1\(\frac{1}{5}\) | |
| -\(\frac{7}{29}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-4a - 1 = \( \frac{a}{7} \)
7 x (-4a - 1) = a
(7 x -4a) + (7 x -1) = a
-28a - 7 = a
-28a - 7 - a = 0
-28a - a = 7
-29a = 7
a = \( \frac{7}{-29} \)
a = -\(\frac{7}{29}\)