ASVAB Math Knowledge Practice Test 369586

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c + 2c = 9c - 6y - 6 for c in terms of y.

\(\frac{1}{4}\)y + 2\(\frac{1}{4}\)
1\(\frac{1}{3}\)y + 1
1\(\frac{1}{10}\)y + \(\frac{4}{5}\)
-\(\frac{7}{11}\)y + \(\frac{3}{11}\)