| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.85 |
| Score | 0% | 57% |
Factor y2 + 2y - 48
| (y + 6)(y - 8) | |
| (y - 6)(y - 8) | |
| (y + 6)(y + 8) | |
| (y - 6)(y + 8) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -48 as well and sum (Inside, Outside) to equal 2. For this problem, those two numbers are -6 and 8. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 2y - 48
y2 + (-6 + 8)y + (-6 x 8)
(y - 6)(y + 8)
If AD = 29 and BD = 25, AB = ?
| 4 | |
| 2 | |
| 10 | |
| 3 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDFind the value of c:
8c + x = -8
8c + 2x = -2
| \(\frac{68}{73}\) | |
| -1\(\frac{3}{4}\) | |
| \(\frac{10}{11}\) | |
| -1\(\frac{21}{31}\) |
You need to find the value of c so solve the first equation in terms of x:
8c + x = -8
x = -8 - 8c
then substitute the result (-8 - 8c) into the second equation:
8c + 2(-8 - 8c) = -2
8c + (2 x -8) + (2 x -8c) = -2
8c - 16 - 16c = -2
8c - 16c = -2 + 16
-8c = 14
c = \( \frac{14}{-8} \)
c = -1\(\frac{3}{4}\)
The dimensions of this trapezoid are a = 5, b = 3, c = 8, d = 4, and h = 4. What is the area?
| 28 | |
| 21 | |
| 14 | |
| 15 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(3 + 4)(4)
a = ½(7)(4)
a = ½(28) = \( \frac{28}{2} \)
a = 14
Simplify (8a)(2ab) - (5a2)(7b).
| 51a2b | |
| -19a2b | |
| 120a2b | |
| 19ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(2ab) - (5a2)(7b)
(8 x 2)(a x a x b) - (5 x 7)(a2 x b)
(16)(a1+1 x b) - (35)(a2b)
16a2b - 35a2b
-19a2b