When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - c = 3c + 8z - 5 for c in terms of z.
| -2\(\frac{4}{5}\)z - 1\(\frac{4}{5}\) | |
| -z - 5 | |
| -9z + 5 | |
| -\(\frac{5}{16}\)z - \(\frac{1}{2}\) |