| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
Find the value of c:
4c + z = 7
-7c + z = -1
| \(\frac{8}{11}\) | |
| -2\(\frac{3}{16}\) | |
| 3\(\frac{1}{20}\) |
You need to find the value of c so solve the first equation in terms of z:
4c + z = 7
z = 7 - 4c
then substitute the result (7 - 4c) into the second equation:
-7c + 1(7 - 4c) = -1
-7c + (1 x 7) + (1 x -4c) = -1
-7c + 7 - 4c = -1
-7c - 4c = -1 - 7
-11c = -8
c = \( \frac{-8}{-11} \)
c = \(\frac{8}{11}\)
The dimensions of this cylinder are height (h) = 4 and radius (r) = 6. What is the volume?
| 12π | |
| 252π | |
| 18π | |
| 144π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(62 x 4)
v = 144π
What is 2a + 3a?
| -a2 | |
| 5a2 | |
| 5 | |
| 5a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
2a + 3a = 5a
Solve for x:
x2 - 5x + 6 = 0
| 9 or -1 | |
| 9 or 6 | |
| 6 or -3 | |
| 2 or 3 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
x2 - 5x + 6 = 0
(x - 2)(x - 3) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x - 2) or (x - 3) must equal zero:
If (x - 2) = 0, x must equal 2
If (x - 3) = 0, x must equal 3
So the solution is that x = 2 or 3
What is the area of a circle with a diameter of 6?
| 9π | |
| 3π | |
| 81π | |
| 6π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{6}{2} \)
r = 3
a = πr2
a = π(32)
a = 9π