ASVAB Math Knowledge Practice Test 372000

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c - 2c = 6c + 5y - 9 for c in terms of y.

\(\frac{3}{14}\)y - \(\frac{1}{7}\)
5\(\frac{2}{3}\)y + 2
6y - 1
-2\(\frac{1}{3}\)y + 3