ASVAB Math Knowledge Practice Test 373819 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

Solve for y:
6y + 9 = \( \frac{y}{9} \)

46% Answer Correctly
-6
4\(\frac{1}{2}\)
\(\frac{12}{49}\)
-1\(\frac{28}{53}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

6y + 9 = \( \frac{y}{9} \)
9 x (6y + 9) = y
(9 x 6y) + (9 x 9) = y
54y + 81 = y
54y + 81 - y = 0
54y - y = -81
53y = -81
y = \( \frac{-81}{53} \)
y = -1\(\frac{28}{53}\)


2

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the area is length x width

all interior angles are right angles

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


3

If side x = 14cm, side y = 11cm, and side z = 12cm what is the perimeter of this triangle?

84% Answer Correctly
29cm
30cm
37cm
31cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 14cm + 11cm + 12cm = 37cm


4

Which types of triangles will always have at least two sides of equal length?

53% Answer Correctly

isosceles and right

equilateral, isosceles and right

equilateral and right

equilateral and isosceles


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


5

Solve for a:
-4a + 6 = 9 + 9a

58% Answer Correctly
-1\(\frac{2}{7}\)
-\(\frac{3}{13}\)
-\(\frac{4}{5}\)
-\(\frac{3}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-4a + 6 = 9 + 9a
-4a = 9 + 9a - 6
-4a - 9a = 9 - 6
-13a = 3
a = \( \frac{3}{-13} \)
a = -\(\frac{3}{13}\)