ASVAB Math Knowledge Practice Test 374050

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a - 5a = -2a - 6z - 5 for a in terms of z.

2\(\frac{2}{7}\)z + 1\(\frac{2}{7}\)
-5z + 3
-\(\frac{2}{15}\)z - \(\frac{2}{15}\)
-\(\frac{1}{4}\)z - 1\(\frac{1}{4}\)