When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b - b = -5b - 9z - 3 for b in terms of z.
-\(\frac{1}{2}\)z - 1\(\frac{1}{6}\) | |
-\(\frac{1}{9}\)z + \(\frac{1}{9}\) | |
2z + 1\(\frac{1}{5}\) | |
-\(\frac{8}{11}\)z - \(\frac{3}{11}\) |