When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve b + 4b = 4b + 2z + 4 for b in terms of z.
| -6\(\frac{1}{2}\)z - 4\(\frac{1}{2}\) | |
| 1\(\frac{6}{7}\)z + 1 | |
| \(\frac{2}{3}\)z - 1\(\frac{1}{3}\) | |
| 1\(\frac{4}{5}\)z - \(\frac{1}{5}\) |