| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.57 |
| Score | 0% | 71% |
The endpoints of this line segment are at (-2, 2) and (2, 0). What is the slope-intercept equation for this line?
| y = -3x + 2 | |
| y = 2\(\frac{1}{2}\)x - 3 | |
| y = 3x - 4 | |
| y = -\(\frac{1}{2}\)x + 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 2) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (2.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)Plugging these values into the slope-intercept equation:
y = -\(\frac{1}{2}\)x + 1
Simplify 5a x 5b.
| 25\( \frac{a}{b} \) | |
| 10ab | |
| 25ab | |
| 25\( \frac{b}{a} \) |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
5a x 5b = (5 x 5) (a x b) = 25ab
Solve for c:
c2 + 12c + 42 = -c + 2
| -8 or -9 | |
| -5 or -8 | |
| 5 or 1 | |
| 7 or -9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
c2 + 12c + 42 = -c + 2
c2 + 12c + 42 - 2 = -c
c2 + 12c + c + 40 = 0
c2 + 13c + 40 = 0
Next, factor the quadratic equation:
c2 + 13c + 40 = 0
(c + 5)(c + 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 5) or (c + 8) must equal zero:
If (c + 5) = 0, c must equal -5
If (c + 8) = 0, c must equal -8
So the solution is that c = -5 or -8
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
pairs |
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exponents |
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division |
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addition |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
A right angle measures:
90° |
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360° |
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180° |
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45° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.