When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 3c = 2c + 4z - 8 for c in terms of z.
| -2\(\frac{1}{6}\)z - \(\frac{1}{6}\) | |
| -\(\frac{2}{7}\)z + 1\(\frac{2}{7}\) | |
| \(\frac{1}{2}\)z - 4 | |
| \(\frac{1}{3}\)z - 1 |