| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.88 |
| Score | 0% | 58% |
Solve 2a + 3a = 5a - 4z + 7 for a in terms of z.
| 2\(\frac{1}{3}\)z - 2\(\frac{1}{3}\) | |
| \(\frac{2}{5}\)z + 1\(\frac{3}{5}\) | |
| -\(\frac{5}{8}\)z - 1\(\frac{1}{8}\) | |
| 2\(\frac{2}{5}\)z - \(\frac{4}{5}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
2a + 3z = 5a - 4z + 7
2a = 5a - 4z + 7 - 3z
2a - 5a = -4z + 7 - 3z
-3a = -7z + 7
a = \( \frac{-7z + 7}{-3} \)
a = \( \frac{-7z}{-3} \) + \( \frac{7}{-3} \)
a = 2\(\frac{1}{3}\)z - 2\(\frac{1}{3}\)
The dimensions of this cylinder are height (h) = 6 and radius (r) = 1. What is the surface area?
| 210π | |
| 108π | |
| 14π | |
| 70π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 6)
sa = 2π(1) + 2π(6)
sa = (2 x 1)π + (2 x 6)π
sa = 2π + 12π
sa = 14π
If BD = 13 and AD = 18, AB = ?
| 6 | |
| 12 | |
| 20 | |
| 5 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDA cylinder with a radius (r) and a height (h) has a surface area of:
π r2h2 |
|
π r2h |
|
4π r2 |
|
2(π r2) + 2π rh |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
What is 7a5 - 2a5?
| 9a10 | |
| 9 | |
| 5a5 | |
| 14a5 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
7a5 - 2a5 = 5a5