ASVAB Math Knowledge Practice Test 377592

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c + 5c = -9c + 3z - 9 for c in terms of z.

-2\(\frac{1}{2}\)z + 1
-2\(\frac{1}{7}\)z + \(\frac{3}{7}\)
1\(\frac{1}{4}\)z - \(\frac{1}{2}\)
-\(\frac{1}{5}\)z - \(\frac{9}{10}\)