When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 3c = 5c + 6z - 9 for c in terms of z.
| 2\(\frac{1}{6}\)z + 1\(\frac{1}{6}\) | |
| 9z - 9 | |
| -\(\frac{1}{2}\)z + 1\(\frac{1}{4}\) | |
| \(\frac{2}{3}\)z - \(\frac{1}{6}\) |