ASVAB Math Knowledge Practice Test 37859 Results

Your Results Global Average
Questions 5 5
Correct 0 2.84
Score 0% 57%

Review

1

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

quadrilateral

triangle

trapezoid

rhombus


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


2

Order the following types of angle from least number of degrees to most number of degrees.

74% Answer Correctly

right, acute, obtuse

right, obtuse, acute

acute, obtuse, right

acute, right, obtuse


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


3

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

intersects

trisects

midpoints

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


4

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
6\( \sqrt{2} \)
9\( \sqrt{2} \)
2\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)


5

Solve for z:
4z - 3 = \( \frac{z}{-8} \)

46% Answer Correctly
\(\frac{8}{11}\)
\(\frac{20}{31}\)
-\(\frac{15}{29}\)
-1\(\frac{1}{2}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

4z - 3 = \( \frac{z}{-8} \)
-8 x (4z - 3) = z
(-8 x 4z) + (-8 x -3) = z
-32z + 24 = z
-32z + 24 - z = 0
-32z - z = -24
-33z = -24
z = \( \frac{-24}{-33} \)
z = \(\frac{8}{11}\)