| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.84 |
| Score | 0% | 57% |
A(n) __________ is to a parallelogram as a square is to a rectangle.
quadrilateral |
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triangle |
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trapezoid |
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rhombus |
A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.
Order the following types of angle from least number of degrees to most number of degrees.
right, acute, obtuse |
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right, obtuse, acute |
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acute, obtuse, right |
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acute, right, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
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trisects |
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midpoints |
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bisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
If the area of this square is 36, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)
Solve for z:
4z - 3 = \( \frac{z}{-8} \)
| \(\frac{8}{11}\) | |
| \(\frac{20}{31}\) | |
| -\(\frac{15}{29}\) | |
| -1\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
4z - 3 = \( \frac{z}{-8} \)
-8 x (4z - 3) = z
(-8 x 4z) + (-8 x -3) = z
-32z + 24 = z
-32z + 24 - z = 0
-32z - z = -24
-33z = -24
z = \( \frac{-24}{-33} \)
z = \(\frac{8}{11}\)