When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 2c = c - 8y + 3 for c in terms of y.
| -3\(\frac{1}{3}\)y + 1 | |
| -\(\frac{1}{3}\)y + 3 | |
| -13y - 4 | |
| -\(\frac{1}{5}\)y + 1 |