When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8a + 2a = -8a + 6y + 3 for a in terms of y.
| 1\(\frac{1}{4}\)y - 2 | |
| -2y - 2 | |
| \(\frac{1}{4}\)y + \(\frac{3}{16}\) | |
| y - 1\(\frac{1}{6}\) |