When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6b + 4b = 5b - 5z + 3 for b in terms of z.
| 1\(\frac{2}{3}\)z - 1 | |
| 14z + 3 | |
| \(\frac{9}{11}\)z - \(\frac{3}{11}\) | |
| z - 1 |