ASVAB Math Knowledge Practice Test 383733 Results

Your Results Global Average
Questions 5 5
Correct 0 3.80
Score 0% 76%

Review

1

If side x = 15cm, side y = 9cm, and side z = 9cm what is the perimeter of this triangle?

84% Answer Correctly
20cm
33cm
29cm
17cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 15cm + 9cm + 9cm = 33cm


2

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

division

exponents

addition

pairs


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


3

A right angle measures:

90% Answer Correctly

180°

360°

90°

45°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


4

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c - a

a2 - c2

c2 - a2

c2 + a2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


5

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
2\( \sqrt{2} \)
\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)