| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
If c = -5 and x = -1, what is the value of -5c(c - x)?
| -198 | |
| 96 | |
| -100 | |
| -12 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-5c(c - x)
-5(-5)(-5 + 1)
-5(-5)(-4)
(25)(-4)
-100
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
|
c - a |
|
a2 - c2 |
|
c2 + a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
The dimensions of this cube are height (h) = 4, length (l) = 7, and width (w) = 9. What is the volume?
| 16 | |
| 252 | |
| 210 | |
| 108 |
The volume of a cube is height x length x width:
v = h x l x w
v = 4 x 7 x 9
v = 252
Solve for y:
-2y - 4 < \( \frac{y}{3} \)
| y < -\(\frac{27}{62}\) | |
| y < -1\(\frac{5}{7}\) | |
| y < 2\(\frac{1}{4}\) | |
| y < \(\frac{24}{25}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-2y - 4 < \( \frac{y}{3} \)
3 x (-2y - 4) < y
(3 x -2y) + (3 x -4) < y
-6y - 12 < y
-6y - 12 - y < 0
-6y - y < 12
-7y < 12
y < \( \frac{12}{-7} \)
y < -1\(\frac{5}{7}\)
Simplify (2a)(9ab) + (7a2)(3b).
| -3ab2 | |
| 110ab2 | |
| 39a2b | |
| 3a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(2a)(9ab) + (7a2)(3b)
(2 x 9)(a x a x b) + (7 x 3)(a2 x b)
(18)(a1+1 x b) + (21)(a2b)
18a2b + 21a2b
39a2b