| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
addition |
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exponents |
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pairs |
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division |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve for b:
8b - 1 < \( \frac{b}{7} \)
| b < \(\frac{7}{55}\) | |
| b < 3\(\frac{1}{5}\) | |
| b < -1\(\frac{1}{7}\) | |
| b < \(\frac{9}{62}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
8b - 1 < \( \frac{b}{7} \)
7 x (8b - 1) < b
(7 x 8b) + (7 x -1) < b
56b - 7 < b
56b - 7 - b < 0
56b - b < 7
55b < 7
b < \( \frac{7}{55} \)
b < \(\frac{7}{55}\)
If a = 1, b = 9, c = 9, and d = 7, what is the perimeter of this quadrilateral?
| 23 | |
| 18 | |
| 26 | |
| 16 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 1 + 9 + 9 + 7
p = 26
The endpoints of this line segment are at (-2, 7) and (2, -5). What is the slope-intercept equation for this line?
| y = -3x - 1 | |
| y = -3x + 1 | |
| y = -2\(\frac{1}{2}\)x + 0 | |
| y = \(\frac{1}{2}\)x - 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 7) and (2, -5) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-5.0) - (7.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)Plugging these values into the slope-intercept equation:
y = -3x + 1
For this diagram, the Pythagorean theorem states that b2 = ?
c - a |
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c2 + a2 |
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a2 - c2 |
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c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)