When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c - c = 2c + 2z - 1 for c in terms of z.
| 2\(\frac{1}{6}\)z - 1\(\frac{1}{2}\) | |
| -\(\frac{3}{5}\)z + \(\frac{1}{5}\) | |
| z - \(\frac{4}{5}\) | |
| -1\(\frac{1}{4}\)z + 2\(\frac{1}{4}\) |