| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.66 |
| Score | 0% | 73% |
Simplify 6a x 7b.
| 42a2b2 | |
| 42ab | |
| 13ab | |
| 42\( \frac{a}{b} \) |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
6a x 7b = (6 x 7) (a x b) = 42ab
Simplify (6a)(8ab) + (6a2)(4b).
| 140ab2 | |
| -24ab2 | |
| 72a2b | |
| 72ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(8ab) + (6a2)(4b)
(6 x 8)(a x a x b) + (6 x 4)(a2 x b)
(48)(a1+1 x b) + (24)(a2b)
48a2b + 24a2b
72a2b
If BD = 18 and AD = 24, AB = ?
| 1 | |
| 17 | |
| 8 | |
| 6 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDOn this circle, line segment AB is the:
radius |
|
circumference |
|
diameter |
|
chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If the area of this square is 49, what is the length of one of the diagonals?
| 7\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)