ASVAB Math Knowledge Practice Test 385275 Results

Your Results Global Average
Questions 5 5
Correct 0 3.66
Score 0% 73%

Review

1

Simplify 6a x 7b.

86% Answer Correctly
42a2b2
42ab
13ab
42\( \frac{a}{b} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

6a x 7b = (6 x 7) (a x b) = 42ab


2

Simplify (6a)(8ab) + (6a2)(4b).

65% Answer Correctly
140ab2
-24ab2
72a2b
72ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(8ab) + (6a2)(4b)
(6 x 8)(a x a x b) + (6 x 4)(a2 x b)
(48)(a1+1 x b) + (24)(a2b)
48a2b + 24a2b
72a2b


3

If BD = 18 and AD = 24, AB = ?

76% Answer Correctly
1
17
8
6

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 24 - 18
AB = 6


4

On this circle, line segment AB is the:

70% Answer Correctly

radius

circumference

diameter

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
4\( \sqrt{2} \)
6\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)