ASVAB Math Knowledge Practice Test 386732

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3a + 3a = 6a - 2y + 1 for a in terms of y.

5y + 3
\(\frac{2}{3}\)y + 1\(\frac{1}{3}\)
\(\frac{5}{9}\)y - \(\frac{1}{9}\)
\(\frac{1}{8}\)y - \(\frac{3}{8}\)