ASVAB Math Knowledge Practice Test 388286

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 8b - 8b = 3b + 6y - 8 for b in terms of y.

2\(\frac{1}{3}\)y + 3
2\(\frac{4}{5}\)y - 1\(\frac{3}{5}\)
\(\frac{1}{6}\)y + \(\frac{2}{3}\)
2y - 1