The surface area of a cylinder is 2πr² + 2πrh:

sa = 2πr² + 2πrh
sa = 2π(6²) + 2π(6 x 2)
sa = 2π(36) + 2π(12)
sa = (2 x 36)π + (2 x 12)π
sa = 72π + 24π
sa = 96π

For parallel lines with a transversal, the following relationships apply:

• angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
• alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
• all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
• same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with d° = 163, the value of a° is 17.

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-7z - 8 < \( \frac{z}{-5} \)
-5 x (-7z - 8) < z
(-5 x -7z) + (-5 x -8) < z
35z + 40 < z
35z + 40 - z < 0
35z - z < -40
34z < -40
z < \( \frac{-40}{34} \)
z < -1\(\frac{3}{17}\)

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

3a - 6 > 4 - 5a
3a > 4 - 5a + 6
3a + 5a > 4 + 6
8a > 10
a > \( \frac{10}{8} \)
a > 1\(\frac{1}{4}\)