| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
Simplify 8a x 6b.
| 14ab | |
| 48a2b2 | |
| 48ab | |
| 48\( \frac{a}{b} \) |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
8a x 6b = (8 x 6) (a x b) = 48ab
Simplify (4a)(5ab) + (6a2)(6b).
| 108a2b | |
| 56ab2 | |
| -16ab2 | |
| 56a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(5ab) + (6a2)(6b)
(4 x 5)(a x a x b) + (6 x 6)(a2 x b)
(20)(a1+1 x b) + (36)(a2b)
20a2b + 36a2b
56a2b
If the area of this square is 4, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
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trisects |
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bisects |
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midpoints |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Which of the following is not required to define the slope-intercept equation for a line?
slope |
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x-intercept |
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y-intercept |
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\({\Delta y \over \Delta x}\) |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.