ASVAB Math Knowledge Practice Test 390584 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

Simplify 8a x 6b.

86% Answer Correctly
14ab
48a2b2
48ab
48\( \frac{a}{b} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

8a x 6b = (8 x 6) (a x b) = 48ab


2

Simplify (4a)(5ab) + (6a2)(6b).

65% Answer Correctly
108a2b
56ab2
-16ab2
56a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(4a)(5ab) + (6a2)(6b)
(4 x 5)(a x a x b) + (6 x 6)(a2 x b)
(20)(a1+1 x b) + (36)(a2b)
20a2b + 36a2b
56a2b


3

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
2\( \sqrt{2} \)
3\( \sqrt{2} \)
4\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)


4

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

intersects

trisects

bisects

midpoints


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


5

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

slope

x-intercept

y-intercept

\({\Delta y \over \Delta x}\)


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.