ASVAB Math Knowledge Practice Test 390822 Results

Your Results Global Average
Questions 5 5
Correct 0 2.66
Score 0% 53%

Review

1

The endpoints of this line segment are at (-2, 1) and (2, -7). What is the slope of this line?

46% Answer Correctly
\(\frac{1}{2}\)
-2
1\(\frac{1}{2}\)
-1

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -7) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-7.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)
m = -2


2

If angle a = 27° and angle b = 59° what is the length of angle d?

56% Answer Correctly
155°
123°
153°
116°

Solution

An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:

d° = b° + c°

To find angle c, remember that the sum of the interior angles of a triangle is 180°:

180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 27° - 59° = 94°

So, d° = 59° + 94° = 153°

A shortcut to get this answer is to remember that angles around a line add up to 180°:

a° + d° = 180°
d° = 180° - a°
d° = 180° - 27° = 153°


3

The dimensions of this cube are height (h) = 3, length (l) = 5, and width (w) = 6. What is the surface area?

51% Answer Correctly
382
14
126
52

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 5 x 6) + (2 x 6 x 3) + (2 x 5 x 3)
sa = (60) + (36) + (30)
sa = 126


4

Simplify (3a)(2ab) + (7a2)(4b).

65% Answer Correctly
22a2b
-22a2b
34a2b
55ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(2ab) + (7a2)(4b)
(3 x 2)(a x a x b) + (7 x 4)(a2 x b)
(6)(a1+1 x b) + (28)(a2b)
6a2b + 28a2b
34a2b


5

Solve for x:
x2 + 3x + 4 = -4x - 2

48% Answer Correctly
6 or -9
8 or 6
-1 or -6
9 or 1

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

x2 + 3x + 4 = -4x - 2
x2 + 3x + 4 + 2 = -4x
x2 + 3x + 4x + 6 = 0
x2 + 7x + 6 = 0

Next, factor the quadratic equation:

x2 + 7x + 6 = 0
(x + 1)(x + 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 1) or (x + 6) must equal zero:

If (x + 1) = 0, x must equal -1
If (x + 6) = 0, x must equal -6

So the solution is that x = -1 or -6