ASVAB Math Knowledge Practice Test 391544 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

Simplify 7a x 3b.

86% Answer Correctly
21ab
10ab
21a2b2
21\( \frac{b}{a} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

7a x 3b = (7 x 3) (a x b) = 21ab


2

The dimensions of this cylinder are height (h) = 9 and radius (r) = 6. What is the surface area?

48% Answer Correctly
112π
44π
168π
180π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 9)
sa = 2π(36) + 2π(54)
sa = (2 x 36)π + (2 x 54)π
sa = 72π + 108π
sa = 180π


3

Which of the following statements about math operations is incorrect?

70% Answer Correctly

all of these statements are correct

you can add monomials that have the same variable and the same exponent

you can multiply monomials that have different variables and different exponents

you can subtract monomials that have the same variable and the same exponent


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


4

Solve for z:
-5z + 3 = \( \frac{z}{-8} \)

46% Answer Correctly
2\(\frac{2}{13}\)
-\(\frac{36}{53}\)
\(\frac{8}{13}\)
3\(\frac{2}{11}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5z + 3 = \( \frac{z}{-8} \)
-8 x (-5z + 3) = z
(-8 x -5z) + (-8 x 3) = z
40z - 24 = z
40z - 24 - z = 0
40z - z = 24
39z = 24
z = \( \frac{24}{39} \)
z = \(\frac{8}{13}\)


5

Solve for c:
c2 - 10c + 25 = 0

58% Answer Correctly
5
2 or -7
-4 or -5
-5 or -8

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c2 - 10c + 25 = 0
(c - 5)(c - 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (c - 5) must equal zero:

If (c - 5) = 0, c must equal 5

So the solution is that c = 5