ASVAB Math Knowledge Practice Test 392316

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 9b - 2b = -3b + y + 1 for b in terms of y.

13y + 5
\(\frac{1}{4}\)y + \(\frac{1}{12}\)
1\(\frac{1}{14}\)y + \(\frac{3}{14}\)
-1\(\frac{1}{4}\)y - 1\(\frac{1}{2}\)