ASVAB Math Knowledge Practice Test 393882

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - 6a = 9a + 7z + 4 for a in terms of z.

1\(\frac{3}{10}\)z + \(\frac{1}{5}\)
16z + 7
1\(\frac{2}{3}\)z - 1\(\frac{1}{3}\)
-2\(\frac{3}{5}\)z - \(\frac{4}{5}\)