ASVAB Math Knowledge Practice Test 39415

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6b + 4b = 2b - 3z - 4 for b in terms of z.

-1\(\frac{3}{4}\)z - 1
2z - \(\frac{4}{5}\)
\(\frac{4}{7}\)z + \(\frac{3}{7}\)
1\(\frac{2}{3}\)z - \(\frac{1}{3}\)