ASVAB Math Knowledge Practice Test 394599

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4a + 5a = a - 4z - 2 for a in terms of z.

-1\(\frac{5}{8}\)z - \(\frac{1}{4}\)
1\(\frac{4}{5}\)z + \(\frac{2}{5}\)
-\(\frac{2}{3}\)z - \(\frac{1}{3}\)
-3z + 7