ASVAB Math Knowledge Practice Test 396446

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -b - 6b = 4b + 9z + 3 for b in terms of z.

-\(\frac{13}{14}\)z - \(\frac{1}{2}\)
\(\frac{1}{2}\)z - 1
-\(\frac{1}{8}\)z + \(\frac{3}{4}\)
-3z - \(\frac{3}{5}\)