When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2c - 3c = 4c + 2y - 1 for c in terms of y.
| -1\(\frac{5}{12}\)y - \(\frac{2}{3}\) | |
| \(\frac{3}{10}\)y + \(\frac{1}{2}\) | |
| \(\frac{3}{5}\)y + \(\frac{1}{5}\) | |
| -\(\frac{5}{6}\)y + \(\frac{1}{6}\) |