| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.28 |
| Score | 0% | 46% |
The dimensions of this cylinder are height (h) = 5 and radius (r) = 5. What is the surface area?
| 100π | |
| 12π | |
| 196π | |
| 6π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(52) + 2π(5 x 5)
sa = 2π(25) + 2π(25)
sa = (2 x 25)π + (2 x 25)π
sa = 50π + 50π
sa = 100π
Solve for a:
-4a + 6 = \( \frac{a}{6} \)
| \(\frac{48}{73}\) | |
| 1\(\frac{11}{25}\) | |
| -\(\frac{18}{35}\) | |
| -\(\frac{21}{34}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-4a + 6 = \( \frac{a}{6} \)
6 x (-4a + 6) = a
(6 x -4a) + (6 x 6) = a
-24a + 36 = a
-24a + 36 - a = 0
-24a - a = -36
-25a = -36
a = \( \frac{-36}{-25} \)
a = 1\(\frac{11}{25}\)
The formula for the area of a circle is which of the following?
c = π d |
|
c = π r2 |
|
c = π r |
|
c = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
The endpoints of this line segment are at (-2, 2) and (2, -2). What is the slope-intercept equation for this line?
| y = -3x + 1 | |
| y = -x + 0 | |
| y = -\(\frac{1}{2}\)x - 4 | |
| y = -1\(\frac{1}{2}\)x + 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 0. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 2) and (2, -2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (2.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)Plugging these values into the slope-intercept equation:
y = -x + 0
What is the area of a circle with a radius of 3?
| 49π | |
| 36π | |
| 25π | |
| 9π |
The formula for area is πr2:
a = πr2
a = π(32)
a = 9π