When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 5c = 2c + 4z + 6 for c in terms of z.
| -z + 1\(\frac{1}{3}\) | |
| \(\frac{3}{4}\)z - \(\frac{5}{8}\) | |
| -\(\frac{1}{6}\)z + 1 | |
| \(\frac{4}{11}\)z + \(\frac{4}{11}\) |