| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.77 |
| Score | 0% | 55% |
Solve for b:
-7b + 9 = -5 - b
| 1 | |
| 1\(\frac{3}{4}\) | |
| 2\(\frac{1}{3}\) | |
| -\(\frac{4}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-7b + 9 = -5 - b
-7b = -5 - b - 9
-7b + b = -5 - 9
-6b = -14
b = \( \frac{-14}{-6} \)
b = 2\(\frac{1}{3}\)
The dimensions of this cylinder are height (h) = 9 and radius (r) = 2. What is the volume?
| 2π | |
| 256π | |
| 36π | |
| 18π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(22 x 9)
v = 36π
Solve for x:
x2 + 12x - 6 = 4x + 3
| -5 or -9 | |
| 3 or 2 | |
| 9 or -2 | |
| 1 or -9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
x2 + 12x - 6 = 4x + 3
x2 + 12x - 6 - 3 = 4x
x2 + 12x - 4x - 9 = 0
x2 + 8x - 9 = 0
Next, factor the quadratic equation:
x2 + 8x - 9 = 0
(x - 1)(x + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x - 1) or (x + 9) must equal zero:
If (x - 1) = 0, x must equal 1
If (x + 9) = 0, x must equal -9
So the solution is that x = 1 or -9
This diagram represents two parallel lines with a transversal. If c° = 12, what is the value of w°?
| 12 | |
| 145 | |
| 153 | |
| 27 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with c° = 12, the value of w° is 12.
Solve -2a - 7a = -9a - 2x + 6 for a in terms of x.
| -\(\frac{9}{10}\)x + \(\frac{3}{10}\) | |
| \(\frac{5}{7}\)x + \(\frac{6}{7}\) | |
| -\(\frac{2}{9}\)x + \(\frac{2}{9}\) | |
| x - \(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-2a - 7x = -9a - 2x + 6
-2a = -9a - 2x + 6 + 7x
-2a + 9a = -2x + 6 + 7x
7a = 5x + 6
a = \( \frac{5x + 6}{7} \)
a = \( \frac{5x}{7} \) + \( \frac{6}{7} \)
a = \(\frac{5}{7}\)x + \(\frac{6}{7}\)