When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3a + 3a = 6a + 5y + 1 for a in terms of y.
| -\(\frac{1}{4}\)y - \(\frac{5}{8}\) | |
| 1\(\frac{6}{7}\)y - 1\(\frac{2}{7}\) | |
| -9y - 5 | |
| -\(\frac{2}{3}\)y - \(\frac{1}{3}\) |