| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.64 |
| Score | 0% | 53% |
If the base of this triangle is 9 and the height is 1, what is the area?
| 75 | |
| 4\(\frac{1}{2}\) | |
| 33 | |
| 36 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 1 = \( \frac{9}{2} \) = 4\(\frac{1}{2}\)
Solve for b:
6b + 6 = 1 - 9b
| -\(\frac{2}{3}\) | |
| -\(\frac{2}{5}\) | |
| -\(\frac{5}{7}\) | |
| -\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
6b + 6 = 1 - 9b
6b = 1 - 9b - 6
6b + 9b = 1 - 6
15b = -5
b = \( \frac{-5}{15} \)
b = -\(\frac{1}{3}\)
Which of the following statements about parallel lines with a transversal is not correct?
all of the angles formed by a transversal are called interior angles |
|
same-side interior angles are complementary and equal each other |
|
angles in the same position on different parallel lines are called corresponding angles |
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all acute angles equal each other |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
Simplify (y - 7)(y - 6)
| y2 + 13y + 42 | |
| y2 - 13y + 42 | |
| y2 + y - 42 | |
| y2 - y - 42 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y - 7)(y - 6)
(y x y) + (y x -6) + (-7 x y) + (-7 x -6)
y2 - 6y - 7y + 42
y2 - 13y + 42
Solve for x:
-5x + 8 = \( \frac{x}{-6} \)
| 1\(\frac{19}{29}\) | |
| 1\(\frac{3}{7}\) | |
| \(\frac{24}{49}\) | |
| -18 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-5x + 8 = \( \frac{x}{-6} \)
-6 x (-5x + 8) = x
(-6 x -5x) + (-6 x 8) = x
30x - 48 = x
30x - 48 - x = 0
30x - x = 48
29x = 48
x = \( \frac{48}{29} \)
x = 1\(\frac{19}{29}\)