When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4b + 5b = -8b - 4z - 8 for b in terms of z.
| 5\(\frac{1}{2}\)z - \(\frac{1}{2}\) | |
| -\(\frac{3}{4}\)z - \(\frac{2}{3}\) | |
| -\(\frac{3}{8}\)z + \(\frac{7}{16}\) | |
| \(\frac{2}{3}\)z + 2 |