ASVAB Math Knowledge Practice Test 402957

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3a + 6a = 3a + 4z + 7 for a in terms of z.

\(\frac{11}{13}\)z + \(\frac{3}{13}\)
\(\frac{1}{3}\)z - 1\(\frac{1}{6}\)
\(\frac{1}{4}\)z - 1
-1\(\frac{2}{3}\)z + \(\frac{1}{2}\)